In the Period 6 inner transition element series, the 4f orbitals begin to be filled after the element _____ La. Thus in the series Sc(II) does not exist, Ti(II) is less stable than Ti(IV). Transition Elements This is due to the electronic configuration of Mn is 3d5 4s2. The completely filled d-orbital makes it highly stable. 4d and 5d orbital’s are spatially larger than 3d (ii) Manganese exhibits the highest oxidation state of +7 among the 3d series of transition elements. Which of the following elements exhibit an irregular filling pattern of the orbitals?-Cu-Cr. The tendency to show highest oxidation state increases from Sc to Mn, then decreases due to pairing of electrons in 3d subshell. The first transition metal Scandium exhibits only +3 oxidation state, but all other transition elements exhibit variable oxidation states by loosing electrons from (n-l)d orbital and ns orbital as … Of oxidation states (7). The fourth 6d-series which begins with Ac is still incomplete. Ti < Zr << Hf (d) In 3d series Cu Zn Density increases Density decreases All transition elements are solid characterized by metallic luster, good conductor of heat and electricity, They have high melting & boiling points due to the strong metallic bond which is formed due to the sharing of both 4S and 3d electrons in the formation of this bond. transition series but elements of 2nd and 3rd transition metal ions often observed a complex behavior Compounds of 1st transition series show High spin nature , the compound of 2nd and 3rd are low spin nature . The density of elements of 3d series across a period: 0; Chemistry ; The decrease in metallic radius coupled with increase in atomic mass results in a general increase in the density of these elements across a period. (b) Os (22.57 gm cm—3) and Ir (22.61 gm cm—3) have highest density. (iv) The enthalpies of atomization of transition metals are quite high. -The 3d orbitals are generally filled after the 4s orbital. The d-block incorporates three series each of ten elements. Answer: 1. These series are portrayed by the totally filled 3d, 4d and 5d subshells and are named as 3d-(first series) Sc - Zn, 4d series (second series) Y-Cd and the 5d series (third series) La-Hg separately. In the first transition series, Cu exhibits +1 oxidation state very frequently. In the 3d series, scandium has the lowest density and copper highest density. Due to lanthanide contraction and a larger decrease in atomic radii and hence, the volume density of 5d series transition elements are double than 4d series. There are two main reasons for this , 1. Describe the variable oxidation state of 3d series elements. Due to lanthanide contraction Ex. In the 3d series, manganese show the highest no. The common oxidation state of 3d series elements is + 2 which arises due to participation of only 4s electrons. It is because Cu ( +1) has an electronic configuration of [Ar] 3d 10. (c) In all the groups (except IIIB) there is normal increase in density from 3d to 4d series, and from 4d to 5d, it increases just double. (Delhi 2011) Answer: (i) Because presence of unpaired d electrons, which undergoes d-d transition by absorption of energy from visible region and … (iii) Manganese exhibits the highest oxidation state of +7 among the 3d series of transition elements. There are mainly three series of the elements, 3d-series (Sc to Zn) 4d-series (Y to Cd) and 5d-series (La to Hg omitting Ce to Lu). orbitals are progressively filled. Enthalpies of atomization of transition metals are quite high exhibits +1 oxidation state of +7 among the 3d of... Copper highest density pairing of electrons in 3d series Cu Zn density density. Period 6 inner transition element series, Cu exhibits +1 oxidation state frequently... First transition series, Cu exhibits +1 oxidation state of +7 among which element exhibits highest density in 3d series series. 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